Theory of Capacitors

Theory of Capacitors

Theory of Capacitors

06/24/16

“Is it possible to store electricity in an electric field?”

Let us consider the following. Two conductive plates are placed on the positive and negative terminals of a circuit with a battery, both in parallel with one another and separated by an insulating material. When the battery turns on, electrons will rush from the “positive” terminal plate, causing a net positive charge on the aforementioned plate. This net charge will then induce electrons to flow from the negative side of the battery to the other plate The balance of these two charges will create an electric field, which in turn will store voltage. This device is called a Capacitor

 We can symbolically analyze capacitors using the equation C=qv, with C being the capacitance, q being the charge, and V being the voltage. Now let’s think about this equation from a real world perspective. We know that Capacitance is caused by a charged particles emiting voltages, so the higher the ratio of maximum charged particles to voltage, the more that this capacitor can store. An equivalent  way to put this equations is C=e*A/D, where e is the electric permittivity constant, A is the area, and d is the distance between the plates. Again, let’s put this in a real world perspective. This seems to be a ratio of the area of the plates to the distance between them, so the more area, the more charge we can store, and the greater distance the smaller the electric potential will be between the charges In addition, we can analyze the energy of the capacitors using the equation E=½ * C* V2, so the more capacitance and voltage, the more energy can be stored in in the object. In summation, capacitors are an intriuing way to store energy

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s